At 10:06 AM 4/22/2004 -0400, Steven C. Barr wrote:

>Then is it the bits (pits and lands) on the CD surface that represent the
>ones and zeros after being processed by an algorithm so that sequences of
>either can be compressed? Thus, reprocessing the ones and zeroes with the
>same algorithm creates the .wav file?
>(decimal:)                           (0)       (63)     (255)    (252)
>Thus, if the waveform in digital is 00000000 00111111 11111111 11111100...
>the actual bits on the CD surface represent the lengths of those strings
>of ones and strings of zeroes rather than the bits that compose the
>digitized
>waveform themselves...right?
>Steven C. Barr

Sorry, Steven. It's much more complicated than that.

The error rate on a CD is very much higher than that on a hard drive or any
other common digital device. As a result, there is a complex relationship
between a group of bits on the disc and the bits representing the current
value. There is a page in the primer at my WWW site - one *not* written by
me, I assure you - on the actual coding used.
   http://www.mrichter.com/cdr/primer/bits.htm


Mike
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