Anyone know how to access the name of the input file when doing an XSLT
transform? I'm using Saxon, command line as follows:
saxon -o testdata/out_file.htm ../xml_files/in_file.xml
../styles/test.xsl
Within my style sheet (test.xsl) I want to be able to get the name of
the input file, in this case in_file.xml, and output it at a particular
spot in out_file.htm. There's got to be a way but I can't seem to find
it.
Michele C.
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Michele R. Combs
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Manuscripts Processor
Special Collections Research Center
Syracuse University Library
222 Waverly Avenue
Syracuse, NY 13244
(315) 443-2697
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