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I was hoping to avoid having to explicitly set a separate variable and
just get it from the input file that's already specified there as the
second argument in the command line... in some languages the command
line parameters are stored and accessible during processing -- you can
use for example arg[1] and arg[2] to retrieve the first and second
command line parameters.  I'm guessing that the intervening layer of the
XSL processor (Saxon or whatever) must prevent that from happening in
XSL?

Michele

>>> [log in to unmask] 2/15/2007 2:05:03 PM >>>
You could do it using parameters:

Add <xsl:param name="filename"/> to the top of your stylesheet

Access the value of the parameter with: <xsl:value-of
select="$filename"/>

Add a 'filename' parameter to the commandline:
 saxon -o testdata/out_file.htm ../xml_files/in_file.xml
../styles/test.xsl filename=in_file.xml


-----Original Message-----
From: Encoded Archival Description List [mailto:[log in to unmask]]On Behalf
Of
Michele Combs
Sent: 15 February 2007 18:43
To: [log in to unmask] 
Subject: Getting name of input file


Anyone know how to access the name of the input file when doing an
XSLT
transform?  I'm using Saxon, command line as follows:

saxon -o testdata/out_file.htm ../xml_files/in_file.xml
../styles/test.xsl

Within my style sheet (test.xsl) I want to be able to get the name of
the input file, in this case in_file.xml, and output it at a
particular
spot in out_file.htm.  There's got to be a way but I can't seem to
find
it.

Michele C.

-=--=--=--=--=--=--=--=--=--=--=--=--=--=-
Michele R. Combs
[log in to unmask] 
Manuscripts Processor
Special Collections Research Center
Syracuse University Library
222 Waverly Avenue
Syracuse, NY 13244
(315) 443-2697
-=--=--=--=--=--=--=--=--=--=--=--=--=--=-

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